4[Z-(6Z+48)+3]=3(Z+9)

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Solution for 4[Z-(6Z+48)+3]=3(Z+9) equation:


Simplifying
4[Z + -1(6Z + 48) + 3] = 3(Z + 9)

Reorder the terms:
4[Z + -1(48 + 6Z) + 3] = 3(Z + 9)
4[Z + (48 * -1 + 6Z * -1) + 3] = 3(Z + 9)
4[Z + (-48 + -6Z) + 3] = 3(Z + 9)

Reorder the terms:
4[-48 + 3 + Z + -6Z] = 3(Z + 9)

Combine like terms: -48 + 3 = -45
4[-45 + Z + -6Z] = 3(Z + 9)

Combine like terms: Z + -6Z = -5Z
4[-45 + -5Z] = 3(Z + 9)
[-45 * 4 + -5Z * 4] = 3(Z + 9)
[-180 + -20Z] = 3(Z + 9)

Reorder the terms:
-180 + -20Z = 3(9 + Z)
-180 + -20Z = (9 * 3 + Z * 3)
-180 + -20Z = (27 + 3Z)

Solving
-180 + -20Z = 27 + 3Z

Solving for variable 'Z'.

Move all terms containing Z to the left, all other terms to the right.

Add '-3Z' to each side of the equation.
-180 + -20Z + -3Z = 27 + 3Z + -3Z

Combine like terms: -20Z + -3Z = -23Z
-180 + -23Z = 27 + 3Z + -3Z

Combine like terms: 3Z + -3Z = 0
-180 + -23Z = 27 + 0
-180 + -23Z = 27

Add '180' to each side of the equation.
-180 + 180 + -23Z = 27 + 180

Combine like terms: -180 + 180 = 0
0 + -23Z = 27 + 180
-23Z = 27 + 180

Combine like terms: 27 + 180 = 207
-23Z = 207

Divide each side by '-23'.
Z = -9

Simplifying
Z = -9

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